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Claim: The average income for college students is below $10,000. What would the

ID: 3022040 • Letter: C

Question

Claim: The average income for college students is below $10,000. What would the null and alternative hypotheses be for this test? H_0: H_A: Explain what a Type 1 error would be for this test. What would the decision rule for this test be? Suppose that a survey of 450 students had an average of $9550 with a standard deviation of However, the sample data suggests that the population has a distribution that is not normal. What would the p-value be for this test? (Show your work.) Given an interpretation of what the p-value means in the context of the problem. If alpha = 0.05, state your conclusion.

Explanation / Answer

A)

Ho: u >= 10000
Ha: u < 10000

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b)

It is concluding that the average income for students is below $10000, when in fact, it is not.

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c)

If we use 0.05 level, then we reject Ho if z < -1.645.

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d)

Formulating the null and alternative hypotheses,              
              
Ho:   u   >=   10000  
Ha:    u   <   10000  
              
As we can see, this is a    left   tailed test.                      
Getting the test statistic, as              
              
X = sample mean =    9550          
uo = hypothesized mean =    10000          
n = sample size =    450          
s = standard deviation =    600          
              
Thus, z = (X - uo) * sqrt(n) / s =    -15.90990258          
              
Also, the p value is              
              
p =    2.70488*10^-57   [ANSWER, P VALUE]

We can still use the normal distirbution because the sampling distribution of the mean is approimately normal by Central Limit Theorem, and we have a big sample size here.

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e)

If the null hypothesis is true, there is only 2.705*10^-57 chance of getting a sample mean this far from 10000.

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f)

There is significant evidence that the true mean income for college students is below $10000 at 0.05 level. [CONCLUSION]
              
Comparing z and zcrit (or, p and significance level), we   REJECT THE NULL HYPOTHESIS.