Course Home Chapter 15 ± Fundamentals of Equilibrium Concentration Calculations

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Course Home Chapter 15 ± Fundamentals of Equilibrium Concentration Calculations K 9 of 16 Consider mixture B, which wll cause the net reaction to proceed forwarod net ? Concentration (M) initial change: (XY) 0.500 - 0.100 +2 0.100+ z 0.100 0.500- 0.100+z The change in concentration r is negative for the reactants because they are consumed and postive for Figure 1 of 1 Part B of XY Based on a K, value of o.180 and the given data table what are the equilibrium X and Y respectively? View Available Hintis) Reaction forms oducts

Explanation / Answer

part B

Kc = [X][Y]/[XY]

[X] = 0.1+x

[Y] = 0.1+x

[XY] = 0.5-x

0.18 = (0.1+x)*(0.1+x)/(0.5-x)

x = 0.15

at equilibrium,

[X] = 0.1+0.15 = 0.25 M

[Y] = 0.1+0.15 = 0.25 M

[XY] = 0.5-0.15 = 0.35 M

part C

Kc = [X][Y]/[XY]

[X] = 0.3-x

[Y] = 0.3-x

[XY] = 0.2+x

0.18 = (0.3-x)*(0.3-x)/(0.2+x)

x = 0.077

at equilibrium,

[X] = 0.3-0.077 = 0.223 M

[Y] = 0.3-0.077 = 0.223 M

[XY] = 0.2+0.077 = 0.277 M

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