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Please include steps 1. An urn contains 6 white (W) and 9 black (B) and 5 green

ID: 3042704 • Letter: P

Question

Please include steps

1. An urn contains 6 white (W) and 9 black (B) and 5 green (G) balls. If 3 balls are randomly selected (assume equally likely outcomes), what is the probability that:

a) Out of the set of three, we select 2 white and 1 black ball

b) Out of the set of three, we select all 3 green balls

c) Out of the set of three, we select all 3 of EQUAL colors (any color)

d) We select a set with at least two colors present in the set of 3 balls.

NOW WE SELECT SEQUENTIALLY AND PAY ATTENTION TO ORDER

e)The first 2 selected are white and the last one is black?

f) The first one is green, the second one is white and the third one is black.

Explanation / Answer

Total balls n = 6 (W) + 9 (B)+ 5 (G) = 20

a ) Out of the set of three, we select 2 white and 1 black ball

Total number of ways to select 3 balls = nC3 = 20C3 = 1140

Number of ways to select 2 whit balls = 6C2 = 15

Number of ways to select 1 black balls = 9C1 = 9

So,

P ( select 2 white and 1 black ball ) = 6C2*9C1 / 20C3 = 0.1184

b) Out of the set of three, we select all 3 green balls.

Number of ways to select 3 green balls = 5C3 = 10

Total ways to select 3 balls = 1140

P( select all 3 green balls ) = 10/1140 = 0.0088

c) Out of the set of three, we select all 3 of EQUAL colors (any color)

We have to find P( select all 3 white or 3 black or 3 green balls )

P( select all 3 of EQUAL colors )

= P( select all 3 white or 3 black or 3 green balls )

= P( select all 3 white balls ) + P( select all 3 black balls ) + P( select all 3 green balls )

= 6C3 / 1140 + 9C3 / 1140 + 5C3 / 1140

= 20/1140 + 84/1140 + 10 / 1140

= 0.1

e )

Probability that first selected ball is white = 6 / 20

Probability that second selected ball is white = 5/19

Probability that third selected ball is black = 9/18

So ,

P(first 2 selected are white and the last one is black )

=6/20 * 5/19 * 9/18

= 0.03947

f )

Probability that first selected ball is green = 5/20

Probability that second selected ball is white = 6/19

Probability that third selected ball is black = 9/18

So,

P ( first one is green, the second one is white and the third one is black )

= 5/20*6/19*9/18

= 0.03947