The most recent fear of walker survivors scores is 41 with an estimated populati

Question

The most recent fear of walker survivors scores is 41 with an estimated population standard deviation of 5.6. Researchers gathered data about how fearful a group of 19 survivors were of attractive walkers of the opposite gender and found the fear score was 39.9,
What kind of procedure is require [type z or t]? What’s the null hypothesis What’s the alternative hypothesis What’s the obtained score Is it one or two tailed What’s the critical value The most recent fear of walker survivors scores is 41 with an estimated population standard deviation of 5.6. Researchers gathered data about how fearful a group of 19 survivors were of attractive walkers of the opposite gender and found the fear score was 39.9,
What kind of procedure is require [type z or t]? What’s the null hypothesis What’s the alternative hypothesis What’s the obtained score Is it one or two tailed What’s the critical value
What kind of procedure is require [type z or t]? What’s the null hypothesis What’s the alternative hypothesis What’s the obtained score Is it one or two tailed What’s the critical value

Explanation / Answer

What kind of procedure is requiring [type z or t]?

Here, we require the z test procedure because we are given a population standard deviation.

What’s the null hypothesis?

Null hypothesis: H0: The average fear score of walker survivors is 41.

H0: µ = 41

What’s the alternative hypothesis?

Alternative hypothesis: Ha: The average fear score of walker survivors is not 41.

Ha: µ 41

What’s the obtained score?

We are given

Sample size = n = 19

Sample mean = Xbar = 39.9

Population standard deviation = = 5.6

Test statistic = z = (Xbar - µ) / [/sqrt(n)]

Z = (39.9 – 41) / [5.6/sqrt(19)]

Z = -1.1/ 1.284728

Z = -0.85621

Obtained score = Z = -0.85621

Is it one or two tailed?

Given test is two tailed.

What’s the critical value?

We are not given a level of significance, so we consider default level of significance as 5% or = 0.05.

Critical value = -1.96 and 1.96 (by using z-table)

P-value = 0.3919

= 0.05

P-value > = 0.05

So, we do not reject the null hypothesis that average fear score of walker survivors is 41.

There is sufficient evidence to conclude that average fear score of walker survivors is 41.

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