Question #9 / 25 Of the people who fished at Clearwater Park today, 36 had a fis

Question

Question #9 / 25 Of the people who fished at Clearwater Park today, 36 had a fishing license, and 24 did not. Of the people who fished at Mountain View Park today, 56 had a license, and 14 did not. (No one fished at both parks.) Suppose that one fisher from each park is chosen at random. What is the probability that the fisher chosen from Clearwater did not have a license and the fisher chosen from Mountain View had a license? Do not round your answer. (If necessary, consult a list of formulas.) Clear Undo Help

Explanation / Answer

Probability that fisher choosen from clearwater did not have license = 24 / (24+36 ) = 0.4

Probability that fisher choosen from mountain view had a license = 56 / (56+14) = 0.8

So,

P( fisher choosen from clearwater did not have license and fisher choosen from mountain view had a license )

=P( fisher choosen from clearwater did not have license)*P(fisher choosen from mountain view had a license )

=0.4*0.8

= 0.32

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