Please do not copy and paste previos answers. Use your own answers with formulas

Question

Please do not copy and paste previos answers. Use your own answers with formulas or brief explanation.

2 of 20 A light ray is incident on a plane mirror with an angle of 50. The reflected angle of the light ray is O greater than 50 O less than 50 O equal to 50 dependent on the index of refraction of the material surrounding the mirror 12 of 20 O real and upright. An object is at a position of 6.0 cm from a diverging lens with a focal length of 3.0 cm. The image can best be described as O real and inverted virtual and upright No image will form. 1 of 20 A light ray traveling through a material with an index of refraction of 1.2 is incident on a material that has an index of refraction of 1.4. Compared to the incident angle, the refracted angle of the light ray is larger than the incident angle smaller than the incident angle equal the incident angle More information is required. It's possible the light ray may not refract at all 20 of 20 You place an arrow in front of a diverging mirror and determine the position of the image. If you place a piece of paper at the image position, what wll you observe on the paper? You will see a large, upright arrow You will see a small, upright arrow O You will see a small, inverted arrow You will not see anything on the paper

Explanation / Answer

2] reflected angle = incident angle = 50 degree , option c

12] third option currect as diverging or concave lens always forms virtual image.

1] second option is correct.

By snells law, n1 sin i = n2 sin r

n2 is larger than n1, sin r has to be less than sin i, or r < i

20] last option, will not see anything on paper because diverging mirror doesnt form real image so cant be caught on screan.

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