I\'m stumped on number 4. Please explain how to solve it, I\'d really appreciate

Question

I'm stumped on number 4. Please explain how to solve it, I'd really appreciate it!

The next two questions (3 and 4) refer to the following: The following frequency distribution displays the speeds (in km/h) for a random sample of vehicles driving on University Crescent. Speed Frequency 40 45 45 50 50 55 55 60 60 65 65 70 70 75 75 80 80 85 15 24 18 3. The distribution of speeds is (A) skewed to the right and so the median is likely greater than the mean. (B) skewed to the left and so the median is likely greater than the mean (C) skewed to the right and so the median is likely less than the mean (D) Wed to the left and so the median is likely less than the mean (E) approximately symmetric and so the median and mean are approximately equal

Explanation / Answer

4)

here from above data

3rd quartile =75th percentile =(np+1) th value =82*0.75 =62.25 th value

from cumulative frequency column we can see that 62.25 th value will fall into interval 55-60

option A is correct

cumulative Bin frequency(f) Frequency 40-45 7 7 45-50 15 22 50-55 24 46 55-60 18 64 60-65 6 70 65-70 5 75 70-75 3 78 75-80 2 80 80-85 2 82 Total 82

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---