I\'m working with applications of motion and I\'m suck on aword problem. The pro

Question

I'm working with applications of motion and I'm suck on aword problem.  
The problem is: Jennifer is twice as old as Ramon. The sum or their ages 7years ago was 13. How old are they now. This problem didn't seem had to me at first, but I just can'tget it down. Thank you for the help. I'm working with applications of motion and I'm suck on aword problem.  
The problem is: Jennifer is twice as old as Ramon. The sum or their ages 7years ago was 13. How old are they now. This problem didn't seem had to me at first, but I just can'tget it down. Thank you for the help.

Explanation / Answer

***More than one way to solve*** Let x = Jennifer's age Let y = Ramon's age This gives us two equations: 1)   x = 2y and 2)   (x - 7) + (y - 7) = 13 If we simplify (x - 7) + (y - 7) = 13 we get x + y- 14 = 13 which is -> x + y = 27 so now we have 2 equations: x = 2y and x + y = 27 If we substitute 2y from 1st equation into 2nd, it changesfrom x + y = 27 to (2y) + y = 27 2y + y = 27 (add like terms) 3y = 27 y = 9 Now use equation(1) to solve for x: x =2y x =2*(9) x =18 So Jennifer is 18and Ramon is 9. So Jennifer is 18and Ramon is 9.

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