A sample of 8080 women is obtained, and their heights (in inches) and pulse rate
ID: 3157453 • Letter: A
Question
A sample of 8080 women is obtained, and their heights (in inches) and pulse rates (in beats per minute) are measured. The linear correlation coefficient is 0.2870.287 and the equation of the regression line is ModifyingAbove y with caret equals 18.5 plus 0.890 xy=18.5+0.890x, where x represents height. The mean of the 8080 heights is 63.663.6 in and the mean of the 8080 pulse rates is 73.873.8 beats per minute. Find the best predicted pulse rate of a woman who is 7272 in tall. Use a significance level of alpha equals 0.05=0.05. LOADING... Click the icon to view the critical values of the Pearson correlation coefficient r. The best predicted pulse rate of a woman who is 7272 in tall is nothing beats per minute. (Type an integer or decimal rounded to two decimal places as needed.
Explanation / Answer
As
y^ = 18.5 + 0.890x
Then for x = 72,
y^ = 18.5 + 0.890*72 = 82.58 beats per minute [ANSWER]
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Hi! The other givens won't matter yet, at least for this part of the question. Thanks!