An object located 3.8 m in front of a plane mirror. The image formed by the mirr

Question

An object located 3.8 m in front of a plane mirror. The image formed by the mirror appears to be 3.8 m in front of the mirror. 1.9 m in front of the mirror. on the mirror's surface. 3.8 m behind the minor's surface. 1.9 m behind the mirror's surface. The optical fiber structure and mechanism of light transmission is shown in the figure. In order for light propagation to occur, total internal reflection should take place at the core/cladding interface. Consider the situation that we wanted to couple the light into the fiber from free space (air) at its end face, i-e., the beam (1) in the figure. What condition does the incident angle (theta_0) have to meet for the light, being, able to propagate in the optic fiber? sin theta_0 n^2/n^1 sin theta_0 Squareroot n^2_1 - n^2_2 sin theta_0 > Squareroot n^2_2 - n^2_1

Explanation / Answer

here,

A plane mirror makes an image of objects in front of it; these images appear to be behind the plane in which the mirror lies

the object distance is 3.8 m in front of the mirror

so, the image formed is

d) 3.8 m behind the mirror's surface

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