Consider the combination of capacitors in the figure below (C_1 = 21.0 mu F, C_2
ID: 3163141 • Letter: C
Question
Consider the combination of capacitors in the figure below (C_1 = 21.0 mu F, C_2 = 2.00 mu F). Find the equivalent single capacitance of the two capacitors in series and redraw the diagram (called diagram 1) with this equivalent capacitance. In diagram 1 find the equivalent capacitance of the three capacitors in parallel and redraw the diagram as a single battery and single capacitor in a loop. Compute the charge on the single equivalent capacitor. Returning to diagram 1, compute the charge on each individual capacitor. 4.00 mu F capacitor mu C 2.00 mu F capacitor mu C 21.0-mu F and 8.00-mu F equivalent capacitor mu C Does the sum agree with the value found in part (c)? What is the charge on the 21.0 mu F capacitor and on the 8-mu F capacitor? Compute the voltage drop across the 21.0 mu F capacitor. Compute the voltage drop across the 2.00 mu F capacitor.Explanation / Answer
d) q = 4 * 36 = 144 muC
q = 2 * 36 = 72 muC
q = (21 * 8 / 21 + 8) * 36 = 208.55 muC
e) Charge on 21 muF capacitor = 208.55 muC
f) V = q / C = 208.55 / 21 = 9.93 volts
g) Votage drop = 36 V