Can you please show all work thank you in advance!!!! In a sample of 900 US. adu
ID: 3171549 • Letter: C
Question
Can you please show all work thank you in advance!!!! In a sample of 900 US. adults, 174 dine out at a resaurant more than once per week. Two us adults are selected random from the population ofall adults at the replacement Assuming the sample is representative of all US. adults, complete parts (a) through (d) (a)Find the probability that both adults dine out more than once per week. The probabaty that both adults dine out more than once per week is (Round to three decimal places as needed. (b) Find the probability that neither adult dines out more than once per week. The probabaity that neither adult dines out more than once per week is (Round to three decimal places as needed) Click to select your answer(s).
Explanation / Answer
In the question from the population of the all US adults (WITH / WITHOUT ) needs to clarified
probability that US adult dine in a restaurant = 174/900 = 0.1933
1) WITHOUT replacement
a) Probability that both dine out = 174/900 * 173/899 = 0.037
b) Proability that no one dine out = 726/ 900 * 725/ 899 = 0.6505
c) Atleast dine out and other not dine out *2) + p(both dine out) = 726/900 * 174/899 * 2 + 0.037 = 0.349
d) option (D) since the prob (a) < 0.05
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WITH replacement
a) Probability that both dine out = 0.1933 * 0.1933 = 0.0373
b) Proability that no one dine out = 0.8067*0.8067 = 0.65
c) Atleast dine out and other not dine out *2) + p(both dine out) = 0.1933* 0.8067*2 + 0.0373 = 0.349
d) option (D) since the prob (a) < 0.05