In a casino game, a die is rolled until two sixes have shown. (a) One bet you ca
ID: 3218142 • Letter: I
Question
In a casino game, a die is rolled until two sixes have shown.
(a) One bet you can make on this game costs $15, regardless of outcome, and has payout as follows. For each time the die is rolled during the game, you get $1. What are the expected winnings (losses count negative) for this bet?
(b) A different bet that the casino offers costs $5, and has payout as follows. If the total number of die rolls in the game is odd, then you get $10, and otherwise you get nothing. (Or you can think of wagering $5, and on the event of an odd number of rolls you get your wager back and an additional $5, and on the event of an even number of rolls you lose your $5 wager.) What are the expected winnings (losses count negative) for this bet?
In a casino game, a die is rolled until two sixes have shown (a) One bet you can make on this game costs $15, regardless of outcome, and has payout as follows. For each time the die is rolled during the game, you get $1. What are the expected winnings (losses count negative) for this bet? (b) A different bet that the casino offers costs $5, and has payout as follows If the total number of die rolls in the game is odd, then you get $10, and otherwise you get nothing. (Or you can think of wagering $5, and on the event of an odd number of rolls you get your wager back and an additional $5, and on the event of an even number of rolls you lose your $5 wager. What are the expected winnings (losses count negative) for this bet?Explanation / Answer
A) Expected number of rolls till 2 sixes are shown = 2x6 = 12
Expected winnings is 12-15 = -$3
means a loss of $3
B) P (odd number of rolls) = 0.5
P (even number of rolls) = 0.5
Expected winnings = (0.5x10) - 5 = $0