Hg) obtained from the same woman. Find the regression equation letting the nght

Question

Hg) obtained from the same woman. Find the regression equation letting the nght arm blood pressure be the predictor C) variable, Find the best Listed below are systolic blood pressure measurements arm is 85 mm Hg. Use a significance level of 0.05. Predicted systolic blood pressure inthe left arm given that the systolic blood pressure in the right 100 92 77 77 Len Arm T 175 169 180 148 148 Click the icon to view the critical values of the Pearson correlation coefficient The regression equaoon is 654 1.1 (Round to one decimal place as needed.) Given that the systolo blood pressure in the right arm is 85 mm Hg, the best predicted systolic blood pressure in the left arm is mm Hg (Round to one decimal place as needed.)

Explanation / Answer

Solution:

Regression Equation(y) = a + bx

Slope(b) = (NXY - (X)(Y)) / (NX2- (X)2)

Intercept(a) = (Y - b(X)) / N

Where, x and y are the variables.

b = The slope of the regression line

a = The intercept point of the regression line and the y axis.

N = Number of values or elements

X = First Score

Y = Second Score

XY = Sum of the product of first and Second Scores

X = Sum of First Scores

Y = Sum of Second Scores

X2 = Sum of square First Scores

X=447

Y=820

X2=40523

Y2=135394

XY=3722055

b=1.102993

a=65.392

Hence prediction equation

y= 65.392+1.1*x

systolic blood pressure in the right arm = 85mm Hg

so x=85

regrssion equation of y on x is given and that is

y=65.4+ 1.1*x,

y=65.4+1.1*85= 158.9

Hence , the best predicted systolic blood pressure in the left arm is 158.9 mm Hg

      right arm(X)        left arm(Y)           X.^2       Y.^2 X*Y 101 175 10201 30625 1030301 100 169 10000 28561 1000000 92 180 8464 32400 778688 77 148 5929 21904 456533 77 148 5929 21904 456533

X=447

Y=820

X2=40523

Y2=135394

XY=3722055

Related Questions

Navigate

• Browse (All)
• Browse H
• Subjects

---