An industrial/organizational psychologist has been consulting with a company tha
ID: 3255951 • Letter: A
Question
An industrial/organizational psychologist has been consulting with a company that runs weekend Job-seeking workshops for the unemployed. Me collected data on several issues related to these workshops and, after conducting statistical tests, obtained statistically significant findings. He needs to find a way to evaluate effect size so that he can make recommendations to the company. One of the psychologist's findings is that immediately after the workshop, a sample of 49 Job seekers who received training on using the Internet to find Job listings scored an average of 6.5 as measured on a 9-point Job-search satisfaction scale, with a standard deviation of 1.2. The typical Job seeker scores 5.8 points. The psychologist finds that the estimated Cohen's d Is _____ the t statistic Is 4.12, and r^2 is _______ Using Cohen's d and Cohen's guidelines for interpreting the effect size with the estimated Cohen's d, there is a _____ treatment effect. Using r^2 and the extension of Cohen's guidelines for Interpreting the effect size using r^2, there is a ____ treatment effect. Another one of the psychologist's findings is that a sample of 144 job seekers who received training on Interview skills worked more than 30 hours an average of 6 9 months in the last year, with a standard deviation of 2.5. The typical Job seeker works 6.4 months.Explanation / Answer
Answer:
Part 1
Effect size Cohen’s d = (6.5-5.8)/1.2 = 0.5833 medium treatment effect
r2 = 4.12^2/ (4.12^2+48) = 0.2612 small treatment effect
part 2
Effect size Cohen’s d = (6.9-6.4)/2.5 = 0.2 small treatment effect
r2 = 2.38^2/ (2.38^2+143) = 0.0381 small treatment effect
small effect size: d = 0.2
medium effect size: d = 0.5
large effect size: d = 0.8
Effect size Cohen’s d = (6.5-5.8)/1.2 = 0.5833 medium treatment effect
r2 = 4.12^2/ (4.12^2+48) = 0.2612 small treatment effect
part 2
Effect size Cohen’s d = (6.9-6.4)/2.5 = 0.2 small treatment effect
r2 = 2.38^2/ (2.38^2+143) = 0.0381 small treatment effect
small effect size: d = 0.2
medium effect size: d = 0.5
large effect size: d = 0.8