I just could not figure out why there is 6 infront this solution(ie. 6 (4/20)(3/

Question

I just could not figure out why there is 6 infront this solution(ie. 6(4/20)(3/19)(5/18)). Rest of the solution is clear but just that is confuse.

2. Twenty pieces of candy are in a jar. 5 of these pieces are orange, 3 are blue, 7 are green, 4 are red, and 1 is brown. Three pieces of candy are randomly selected without replacement. What is the probability that: a) All three pieces are green? P(3 are green) = ( )(0%)-0840 b) One of the pieces is red, one is blue, and one is orange? P (one red, one blue, and one orange) = 6(20)(19)(18) = 6840 n) = ( )( )(18) _ 6840 4, 3,5 360

Explanation / Answer

6 is there because of 3!

note that we have to take three type of candy ,

(4*3*5) /(20*19*18) does not consider the order in which different candy can come

for example

RBO, ,BOR ,.. etc are different ways in which given condition is true ,

first red , then blue , and then orange

next way

first blue, then orange , and then red

we know that arrangement of n place is n!

here n = 3

hence

n! = 6

Please rate

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---