Subject. Probability & statistics Please answer it ASAP. Number...., 4 Show all
ID: 3312302 • Letter: S
Question
Subject. Probability & statisticsPlease answer it ASAP.
Number...., 4 Show all work in details for each question. Poists: Q-Qs 4Q-1,EC-2 1. The chances of having a set of natural quadruplets is 1 in 500,000 in a certain population. What is the probability that there will be at least two sets d natural quadruplets among a random sample of 640,000 people? 2. A weighted die for which the probability of obtaining a 'even' is 0.2 and clearly the probability obtaining an 'odd' outcome is 0.8. If one were to roll this die 7 3. Suppose that X and Y are independent random variables whose variances exist 4. Assume that you are a tabletop role-playing game that requires one to use 2 times, compute the probability of obtaining 4 or more 'odd' outcomes? and such that E(X) = E(Y). Compute El(X-Y) four-sided (tetrahedral) dice (a.k.a numbers 1-4 are the only options for each dice). Compute the expected value and variance for a roll of two such dice. 5. Suppose that one letter is to be selected randomly from the letters in the sentence given: If Y denotes the number of letters in the word in which the selected letter appears, what is the expected value of the random variable Y? Habemus Novum Balneum Vapore Imbrem In Nobis Palam 6. Suppose that Amber and Dana make an appointment to meet between 3 and 4 pm at a Coffee Shop, and they agree that neither person will wait more than 15 minutes for the other person. If they arrive independently at random times between 3 and 4 pm, what is the probability they will meet? 7. Suppose that a random variable X can take only the values 'm' and 'n' with the following probabilities: P(X = m) = p and P(Xen)-1-p Express the p.f. of X in form of the definition of f(xlp) 8. Suppose that X has the Uniform distribution on the interval la.bl. Compute the Variance of X.
Explanation / Answer
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2) Even = 0.2
Odd = 0.8
n = 7
P(X 4 odd) = 7C4 * 0.8^4 * 0.2^3 + 7C5 * 0.8^5 * 0.2^2 + 7C6 * 0.8^6 * 0.2^1 + 7C7 * 0.8^7 * 0.2^0
P = 0.967