According to Masterfoods, thecompany that manufactures M&M;\'s 12% of peanut M&M
ID: 3328081 • Letter: A
Question
According to Masterfoods, thecompany that manufactures M&M;'s 12% of peanut M&M;'s are bro 15% are yellow, 12% are red, 23% are blue, 23% are orange and 1 5% are green. Round your answe three decimal places, for example: 0.123] 100% Compute the probability that a randomly selected peanut M&M; is not blue. 17 Compute the probability that a randomly selected peanut M&M; is yellow or red. 0.35 Compute the probability that two randomly selected peanut M&M;'s are both blue. compute that probability that neither of them are red. If you randomly select two peanut M&M;'s, If yo u randomly select two peanut M&M;'s, compute that probability that at least one of them is red.Explanation / Answer
P(Brown) = 0.12 P(Yellow) = 0.15 P(Red) = 0.12 P(Blue) = 0.23 P(Orange) = 0.23 P(Green) = 0.15
1. P(Not Blue) = 1 - P(Blue) = 1 - 0.23 = 0.77.
2. P(Yellow or Red) = P(Yellow) + P(Red) = 0.15 + 0.12 = 0.27.
3. P(Blue) = 0.23
=> Probability that two randomly selected M&Ms are blue = 0.23 * 0.23 = 0.0529.
4. P(Not Red) = 1 - P(Red) = 1 - 0.12 = 0.88
=> Probability that neither is red = 0.88 * 0.88 = 0.7744.
5. P(Atleast one is Red) = 1 - P(Neither is red) = 1 - 0.7744 = 0.2256.