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Consider the following output for an autoregressive forecasting model Coefficien

ID: 3333171 • Letter: C

Question

Consider the following output for an autoregressive forecasting model

Coefficients

Standard Error

t Statistic

p-value

Intercept

5.745787

4.85094

0.84426

0.40299

yt-1

0.62849

-0.10434

-1.66023

0.103822

yt-2

0.65709

0.962669

14.65044

9.69E-19

The actual values of this time series, y, were 228, 54, and 191 for May, June, and July, respectively. The predicted (forecast) value for August is:

36.91

161.27

218.71

83.67

Coefficients

Standard Error

t Statistic

p-value

Intercept

5.745787

4.85094

0.84426

0.40299

yt-1

0.62849

-0.10434

-1.66023

0.103822

yt-2

0.65709

0.962669

14.65044

9.69E-19

Explanation / Answer

Solution:

The forecast equation is given as below:

Predicted (forecast) value = yt = 5.745787 + 0.62849*yt-1 + 0.65709*yt-2

[ We have, t = August, t – 1 = July, t – 2 = June, t – 3 = May ]

Predicted (forecast) value = yt =5.745787 + 0.62849*July value+ 0.65709*June value

Predicted (forecast) value = yt =5.745787 + 0.62849*191+ 0.65709*54

Predicted (forecast) value = yt =161.2702

Correct answer = 161.27