Please explain step by step A researcher has developed an intervention that may

Question

Please explain step by step

A researcher has developed an intervention that may influence optimism. He collects optimism scores from a sample of 30 adults before and after administering the intervention, and conducts a t-test for dependent samples. The sample mean before the intervention is 55.7, and after the intervention is 61.3, and 2.6 is the standard error of the difference between means. For a two-tailed test with alpha = 0.05, with a critical value of 2.04, what is the t ratio and what should his decision be? Ot 2.15, fail to reject the null hypothesis O t-347, reject the null hypothesis Ot 3.47, fail to reject the null hypothesis Ot-2.15, reject the null hypothesis

Explanation / Answer

here mean difference d=61.3-55.7=5.6

therefore t ratio =difference/std error =5.6/2.6 =2.15

as t ratio is greater then 2.04 critical value we reject null hypothesis

t=2.15; reject the null hypothesis option is correct

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