If you could explain how you got it that would be awesome. Thank you! Suppose yo
ID: 3431731 • Letter: I
Question
If you could explain how you got it that would be awesome.
Thank you!
Suppose you are interested in whether a particular die is fair or it comes up 6 50% of the time. You get to roll the die twice and see how many times it comes up 6. There are two possible actions a 1 is the action of concluding the die is fair and a 2 is the action of concluding that the die comes up 50% of the time. The question is to find the risk of each decision rule. I understand how to do that I am just confused on finding p (x = 0) wt Theta 1 If Theta 1 = 1 die is fair and theta 2= die comes up 6 50% of the time, what would these be? If you could explain how you got it that would be awesome. Thank you!Explanation / Answer
1) p(x=0) WRT THETA1 means P(X=0) when die is fair.
= 0 as 0 cannot be shown on a die
2) P(X=1) when die is fair = 1/6
3) P(X=2) when die is fair = 1/6
4) P(X=0) when die is biased =0 (as 0 cannot be shown on a die)
5) P(x=1) when die is biased = 1/5(1-0.5) =0.1
6) P(X=2) when die is biased = 0.1
Note that wrt theta 1 means die is fair and theta2 means die is biased with 6 showing 0.5 time
Hence other number prob = 0.1