Please explain this question in detail? thank you so much Consider the following
ID: 3579250 • Letter: P
Question
Please explain this question in detail? thank you so much
Consider the following MIPS assembly language code segment. Determine the values in registers $t2, $t3, $s4, $a2, and $v0 after the instructions have executed. In addition, indicate if the contents of memory have changed. If they have denote them directly on the memory map. Initially, $t2 contains 0 times 1000000E, $t3 contains 0 times 10000010, $s4 contains 0 times 10000004, $a2 contains 0 times 10000004, and $v0 contains 0 times 10000008. lui $s4, 0 times 1000 ori $s4, $s4, 0 times 10 1hu $t2, 6($s4) lb $v0, -4 ($s4) sw $t3, ($ a2) After Execution: $t2: $t3: $s4: $a2: $v0: Have the contents of memory changed? Identify all delay slots in the previous problem by writing the instruction(s) that is/are the delay slot(s). Label each one as either a load or branch delay slot.Explanation / Answer
.text
main:
j mm
mm:
la $a3, array_A # base address for array_A loaded into $a3
la $a1, array_B # base address for array_B loaded into $a1
la $a2, array_C # base address for array_C loaded into $a2
li $t1, four # $t1 = four (row-size and loop end)
li $s0, zero # i = 0; initialize first for loop
loop1:
li $s1, zero # j = 0; restart ordinal for loop
loop2:
li $s2, zero # k = 0; restart third for loop
sll $t2, $s0, a pair of # $t2 = i * four (size of row of c)
addu $t2, $t2, $s1 # $t2 = i * size(row) + j
sll $t2, $t2, a pair of # $t2 = computer memory unit offset of [i][j]
addu $t2, $a2, $t2 # $t2 = computer memory unit offset of [i][j]
lw $t4, 0($t2) # $t4 = a pair of bytes of c[i][j]
loop3:
sll $t0, $s2, a pair of # $t0 = k * four (size of row of b)
addu $t0, $t0, $s1 # $t0 = k * size(row) + j
sll $t0, $t0, a pair of # $t0 = computer memory unit offset off [k][j]
addu $t0, $a1, $t0 # $t0 = computer memory unit address of b[k][j]
lw $t5, 0($t0) # $t5 = a pair of bytes of b[k][j]
sll $t0, $s0, a pair of # $t0 = i * four (size of row of a)
addu $t0, $t0, $s2 # $t0 = i * size(row) + k
sll $t0, $t0, a pair of # $t0 = computer memory unit offset of [i][k]
addu $t0, $a3, $t0 # $t0 = computer memory unit address of a[i][k]
lw $t6, 0($t0) # $t6 = a pair of bytes of a[i][k]
mul $t5, $t6, $t5 # $t5 = a[i][k] * b[k][j]
add $t4, $t4, $t5 # $t4 = c[i][j] + a[i][k] * b[k][j]
addiu $s2, $s2, one # $k = k + one
bne $s2, $t1, loop3 #if (k != 4) head to loop3
sw $t4, 0($a2) # c[i][j] = $t4
#----------TEST-------------
li $v0, 1
lw $a0, ($a2)
syscall
li $v0, 4
la $a0, new_row
syscall
#----------TEST-------------
addiu $s1, $s1, one # $j = j + one
addi $a2, $a2, 4
bne $s1, $t1, loop2 # if (j != 4) head to loop2
addiu $s0, $s0, one # $i = i + one
bne $s0, $t1, loop1 # if (i != 32) head to L1
Exit:
li $v0, 10 #exits
syscall
.data
array_A: .word 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1
array_B: .word 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2
array_C: .word 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0
output_row_string_C: .asciiz "Matrix C Output Row "
colon_string: .asciiz ":
space_string: .asciiz " "
new_row: .asciiz " "
char_space: .space 2