Please i need answer to this Q as soon as possible... Q) Consider compressed vid
ID: 3664140 • Letter: P
Question
Please i need answer to this Q as soon as possible...
Q) Consider compressed video transmission in an ATM network. Suppose standard ATM cells must be transmitted through 5 switches. The data rate is 43 Mbps.
a. What is the transmission time for one cell through the switch?
b. Each switch may be transmitting a cell from other traffic all of which we assume to have lower (non-preemptive for the cell) priority. If the switch is busy transmitting a cell, our cell has to wait until the other cell completes transmission. If the switch is free our cell is transmitted immediately. What is the maximum time from when a typical video cell arrives at the first switch (and possibly waits) until it is finished being transmitted by the fifth and last one? Assume that you can ignore propagation time, switch time, and everything else but the transmission time and the time spent waiting for another cell to clear a switch.
c. Now suppose we know that each switch is utilized 60% of the time with the other low-priority traffic. By this we mean that with probability 0.6 when we look at a switch it is busy. Suppose that if there is a cell being transmitted by a switch, the average delay spent waiting for a cell to finish transmission is one-half a cell’s transmission time. What is the average time from the input of the first switch to clearing the fifth?
d. However, the measure of the most interest is not delay but jitter, which is the variability in the delay. Use parts (b) and (c) to calculate the maximum and average variability, respectively, in the delay.
Explanation / Answer
I know that the length of ATM cell is 53 bytes (48+5) and also, RT-VBR is used for compressed video. But, I don't know how to calculate the delay, jitter etc.
A......PROTOCOLS AND THE TCP/IP SUITE4.1The network access layer is concerned with the exchange ofdata between acomputer and the network to which it is attached.4.2The transport layer is concerned with data reliabilityand correct sequencing.4.3A protocol is the set of rules or conventions governing the way in which twoentities cooperate to exchange data.4.4A PDU is the combination of data from the next highercommunications layer andcontrol information.4.5The software structure that implements the communications function. Typically,the protocol architecture consists of a layered set of protocols, with one or moreprotocols at eachlayer.4.6Transmission Control Protocol/Internet Protocol (TCP/IP) are two protocolsoriginally designed to provide low level support for internetworking. The term isalso used generically torefer to a more comprehensive collection of protocolsdeveloped by the U.S. Department of Defense andthe Internet community.4.7Layering decomposes the overall communications problem into a number ofmoremanageable subproblems.4.8A router is a device that operates at the Network layer of the OSI modelto connectdissimilar networks
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B..........These questions are very vague and dependant on lots of variables -- most of which aren't supplied. Is this a question you have in your studies, ambis?
C.......These questions are very vague and dependant on lots of variables -- most of which aren't supplied. Is this a question you have in your studies, ambis?
D......know that the length of ATM cell is 53 bytes (48+5) and also, RT-VBR is used for compressed video. But, I don't know how to calculate the delay, jitter etc.