I have to translate C++ code into MIPS. It is expected to have an output of: Val
ID: 3846694 • Letter: I
Question
I have to translate C++ code into MIPS. It is expected to have an output of: Value of a: 25 Value of b: 31 Value of c: 18 Value of d: 49
Here is the C++ code:
I need to translate this C++ into MIPS code.
Here is what was give.
.data
endl: .asciiz " " # used for cout << endl;
albl: .asciiz "Value of a: " # label for a
blbl: .asciiz "Value of b: " # label for b
clbl: .asciiz "Value of c: " # label for c
dlbl: .asciiz "Value of d: " # label for d
.text
# a --> $s0
# b --> $s1
# c --> $s2
# d --> $s3
main:
(fill in here)
exit:
la $a0, albl # puts albl into arg0 (a0 register) for cout
addi $v0, $0, 4 # puts 4 in v0 which denotes we are printing a string
syscall # make a syscall to system
move $a0, $s0 # puts a into arg0 (a0 register) for cout
addi $v0, $0, 1 # puts 1 in v0 to denote we are printing an int
syscall # make a syscall to system
la $a0, endl # puts the address of the string endl into a0
addi $v0, $0, 4 # puts 4 into v0 saying we are printing a string
syscall
la $a0, blbl # puts blbl into arg0 (a0 register) for cout
addi $v0, $0, 4 # puts 4 in v0 which denotes we are printing an string
syscall # make a syscall to system
move $a0, $s1 # puts b into arg0 (a0 register) for cout
addi $v0, $0, 1 # puts 1 in v0 to denote we are printing an int
syscall # make a syscall to system
la $a0, endl # puts the address of the string endl into a0
addi $v0, $0, 4 # puts 4 into v0 saying we are printing a string
syscall
la $a0, clbl # puts clbl into arg0 (a0 register) for cout
addi $v0, $0, 4 # puts 4 in v0 which denotes we are printing a string
syscall # make a syscall to system
move $a0, $s2 # puts c into arg0 (a0 register) for cout
addi $v0, $0, 1 # puts 1 in v0 to denote we are printing an int
syscall # make a syscall to system
la $a0, endl # puts the address of the string endl into a0
addi $v0, $0, 4 # puts 4 into v0 saying we are printing a string
syscall
la $a0, dlbl # puts dlbl into arg0 (a0 register) for cout
addi $v0, $0, 4 # puts 4 in v0 which denotes we are printing a string
syscall # make a syscall to system
move $a0, $s3 # puts d into arg0 (a0 register) for cout
addi $v0, $0, 1 # puts 1 in v0 to denote we are printing an int
syscall # make a syscall to system
la $a0, endl # puts the address of the string endl into a0
addi $v0, $0, 4 # puts 4 into v0 saying we are printing a string
syscall
addi $v0,$0, 10
syscall
Explanation / Answer
Got your main code here
li $s0, 5 # load value 5, into $s0 [i.e, a]
li $s1, 6
li $s2, 7
li $s3, -1
li $t0, 10
slt $t1, $s0, $t0 # is a<10?
beq $t1, 0, ELSE1 # if no, then go to else part
add $s0, $s0, 1 # if yes, then increment a by 1
j ENDIF1 # end of if
ELSE1 :
addi $s0, $s0, -1 # decrement a by 1
ENDIF1 :
add $s3, $s0, $s2 # d=a+c
add $s2, $s0, $s3 # c=a+d
slt $t1, $s1, $t0 # is b<10?
beq $t1, 0, ELSE2 # if no, then go to else part
add $s1, $s1, 1 # if yes, then increment b by 1
addi $s2, $s2, -1 # and decrement, c by 1
j ENDIF2 # end of if
ELSE2 :
addi $s1, $s1, -1 # decrement b by 1
add $s2, $s2, 1 # and increment, c by 1
ENDIF2 :
add $s0, $s2, $s1 # a=c+b
add $s1, $s2, $s3 # b=c+d
slt $t1, $s1, $s2 # is (b<c)?
slt $t2, $s0, $s1 # is (a<b)?
beq $t1, 0, ELSEIF # if false, then go to ELSEIF
beq $t2, 0, ELSEIF # if false, then go to ELSEIF
add $s3, $s0, $s1 # if true, d=a+b
j DONE # DONE
ELSEIF :
slt $t1, $s2, $s1 # is (c<b)?
slt $t2, $s2, $s0 # is (c>a)?
beq $t1, 1, LABEL # if true, goto LABEL
beq $t2, 1, LABEL # if true, goto LABEL
j DONE # if false, then DONE
LABEL:
add $s3, $s1, $s2 # d=b+c
DONE :