Following the bit-level floating point coding rules, implement the floating-poin

Question

Following the bit-level floating point coding rules, implement the floating-point add and multiply function with the following prototype. — typedef unsigned float_bits;
float_bits float_add (float_bits x, float_bits y) ; float_bits float_multiply (float_bits x, float_bits y) ; Following the bit-level floating point coding rules, implement the floating-point add and multiply function with the following prototype. — typedef unsigned float_bits;
float_bits float_add (float_bits x, float_bits y) ; float_bits float_multiply (float_bits x, float_bits y) ; — typedef unsigned float_bits;
float_bits float_add (float_bits x, float_bits y) ; float_bits float_multiply (float_bits x, float_bits y) ;

Explanation / Answer

n this case, X is 1.01 X 22 and Y is 1.11 X 20.

For now, the resulting exponent is 2 + 0 = 2

Multiplying 1.01 by 1.11 results in 10.0011

Now, we have to renormalize 10.0011 to 1.00011 and increase the exponent by 1 to 3

The sign bit is 0 + 0 = 0.

We need to truncate 1.00011 x 23 to 1.000 x 23 and convert.

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