Please thoroughly explain your solution and I would prefer it written out oppose

Question

Please thoroughly explain your solution and I would prefer it written out opposed to be just typed. Please and thank you.

A capacitor consists of two charged disks of radius 4 m separated by a distance s - 2 mm (see the figure). The magnitude o* the charge on each disk is mC. Consider points A. B, c. and O inside the capacitor, as shown in the diagram. The distance s1 = 1. 3 mm, and the distance s2 = 0. 5 mm. (Assume the +x axis is to the right, the +y axis Is up. and the +z axis is out. ) What is the electric field inside the capacitor? First, calculate the potential deference VB - VA. What is along this path? Next, calculate the potential difference Vc - l/g. Finally, calculate the potential difference Va - Vc. What is A along this path?

Explanation / Answer

We have charge Q,area A,distance s.

So we have capacitance C=epsilon*A/s.

And pot. diff. V=Q/C.

Now electric field E=V/s(which is only in + x axis direction)

The pot. diff is simply E.d(dot product between field and displacement vector).

Since the field has no 'Y' or 'Z' component,we need only displacement in X direction.

For A and B,pot. diff is E*s1.

For B and C,both have same X coordinate.distance between them is zero(only in X direction).

So their potential diff of 'zero'

Now for A and C(this is same as A and B) since same displacement in X direction.

their pot. diff. E*s1.

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