For the circuit in the figure ( Figure 1 ) , R = 140 ? , L = 0.900 H and C = 5.0

Question

For the circuit in the figure (Figure 1) , R = 140? ,L = 0.900H and C = 5.00?F . When the source is operated at the resonance frequency, the current amplitude in the inductor is 0.400A . For the circuit in the figure (Figure 1) , R = 140? ,L = 0.900H and C = 5.00?F . When the source is operated at the resonance frequency, the current amplitude in the inductor is 0.400A . For the circuit in the figure (Figure 1) , R = 140? ,L = 0.900H and C = 5.00?F . When the source is operated at the resonance frequency, the current amplitude in the inductor is 0.400A . For the circuit in the figure (Figure 1) , R = 140? ,L = 0.900H and C = 5.00?F . When the source is operated at the resonance frequency, the current amplitude in the inductor is 0.400A . Part A Determine the current amplitude in the branch containing the capacitor. IC =   A   SubmitMy AnswersGive Up Part B Determine the current amplitude through the resistor. IR =   A   SubmitMy AnswersGive Up Provide FeedbackContinue Part A Determine the current amplitude in the branch containing the capacitor. IC =   A   SubmitMy AnswersGive Up Part B Determine the current amplitude through the resistor. IR =   A   SubmitMy AnswersGive Up Part A Determine the current amplitude in the branch containing the capacitor. IC =   A   SubmitMy AnswersGive Up Part B Determine the current amplitude through the resistor. IR =   A   SubmitMy AnswersGive Up Part A Determine the current amplitude in the branch containing the capacitor. IC =   A   SubmitMy AnswersGive Up Part B Determine the current amplitude through the resistor. IR =   A   SubmitMy AnswersGive Up Part A Determine the current amplitude in the branch containing the capacitor. IC =   A   SubmitMy AnswersGive Up Part A Determine the current amplitude in the branch containing the capacitor. IC =   A   SubmitMy AnswersGive Up IC =   A   IC =   A   SubmitMy AnswersGive Up Part B Determine the current amplitude through the resistor. IR =   A   SubmitMy AnswersGive Up Part B Determine the current amplitude through the resistor. IR =   A   SubmitMy AnswersGive Up IR =   A   IR =   A   SubmitMy AnswersGive Up Provide FeedbackContinue Figure 1 of 1 For the circuit in the figure (Figure 1) , R = 140? ,L = 0.900H and C = 5.00?F . When the source is operated at the resonance frequency, the current amplitude in the inductor is 0.400A . Part A Determine the current amplitude in the branch containing the capacitor. IC =   A   SubmitMy AnswersGive Up Part B Determine the current amplitude through the resistor. IR =   A   SubmitMy AnswersGive Up Provide FeedbackContinue Figure 1 of 1

Explanation / Answer

when operated at resosance Z = R

so current across inductor = current across cacpatior

so I across C = 0.4 Amps

b. as Z = R,   current across R = 0.4 A

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