Describe how the 1-D integer array s[4] in v7 is laid out in main memory (i.e.,

Question

Describe how the 1-D integer array s[4] in v7 is laid out in main memory (i.e., RAM). What is contained at s?

// Pointers and arrays

#include <stdio.h>

int main()

{

int s[4];

s[0] = 100;

s[1] = 200;

s[2] = 300;

s[3] = 400;

printf("%d ",s[0]);

printf("%d ",s[1]);

printf("%d ",s[2]);

printf("%d ",s[3]);

printf("%d ",*s);

printf("%d ",*(s+1));

printf("%d ",*(s+2));

printf("%d ",*(s+3));

*s = 1000;

*(s+1) = 2000;

*(s+2) = 3000;

*(s+3) = 4000;

printf("%d ",*s);

printf("%d ",*(s+1));

printf("%d ",*(s+2));

printf("%d ",*(s+3));

}

Explanation / Answer

In memory: s is an array. Structure of S in memory is -------------------------------------------- | Address | x | x + 4 | x + 8 | x + 12 | -------------------------------------------- | Values | s[0] | s[1] | s{2} | s{3} | -------------------------------------------- Where x is the initial address of the array. ====================================================== Final values of the array is [1000,2000,3000,4000]

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