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Please do the graph for the following a, b and c Par Inc.’s production is constr

ID: 408510 • Letter: P

Question

Please do the graph for the following a, b and c

Par Inc.’s production is constrained by a limited number of hours available in each department. After studying departmental workload projections, the director of manufacturing estimates that 630 hours for cutting and dyeing, 600 hours for sewing, 708 hours for fiishing, and 135 hours for inspection and packaging will be available for the production of golf bags during the next three months.

The accounting department analyzed the production data, assigned all relevant variable costs, and arrived at prices for both bags that will result in a profi contribution1 of $10 for every standard bag and $9 for every deluxe bag produced. Let us now develop a mathematical model of the Par, Inc., problem that can be used to determine the number of standard bags and the number of deluxe bags to produce in order to maximize total profit contribution.

For each of the following independent situations, select the correct graph which shows the optimal solution and the total profit contribution:

The accounting department revises its estimate of the profit contribution for the deluxe bag to $18 per bag.

A new low-cost material is available for the standard bag, and the profit contribution per standard bag can be increased to $20 per bag. (Assume that the profit contribution of the deluxe bag is the original $9 value.)

New sewing equipment is available that would increase the sewing operation capacity to 750 hours. (Assume that 10A + 9B is the appropriate objective function.)

Explanation / Answer

Answer:

Let A is the number of standard bad

and B is the number of units for delux bag

Now we have total number of hours = to produce both the bags = 2073

Therefore we have

A+ B <= 2073

now we have two regions and two points:

one is (0, 2073) and the other is (2073,0)

The objective function Z = 10A + 9B

Therefore:

Z at (0,2073) = $18,965

Z at (2073,0) = $20,730

Therefore the feasible solution is (2073,0).