Please do the lab report (Tell me he results of the experiment and the conclusio
ID: 2249457 • Letter: P
Question
Please do the lab report (Tell me he results of the experiment and the conclusions)Look at the procedure and state what happens iPad 7:07 PM ECE-227 Lab Manual 080617.pdf 39 Experiment 10: Multifunction Register Objectives: To apply the methods for sequential circuit design developed in ECE 226 class to the design of a complicated register and to become familiar with the multiplexer Materials Needed: 2--74LS74 TTL IC 2--74LS153 TTL IC 1-74LS04 TTL IC Introduction: Registers are an important building component in every computer. Most registers found in computers are multifunction, that is they are capable of implementing a number of functions as shift-left, shift-right, clear, complement, parallel load, etc. Furthermore, the shift functions can be further classified as logical shifts, arithmetic shifts and circular shifts. Prelab Referring to your textbook and using the material presented in ECE 226 class, design a four bit multifunction register. It works in four modes as listed below: 1. No chaneThe state (outputs) of the register will not change even though clock pulses are continuously applied. 2. Shift right … 3. Shift leftIt acts as a shift left register 4, Parallel load-…… The register could be loaded in parallel. It acts as four l-bit It acts as shift right register data registers There are two selection lines S1, S0 for selecting the proper mode. The following table gives a list of mode control by SO and SI Open with G Print
Explanation / Answer
The IC 74LS153 in a dual 4-input multiplexer IC i.e. this IC consists of 2 4:1 mux. Pin 7 and 9 are the output pins of the two multiplexers in the IC.
(2)
When S0=S1=1 in 74LS153 IC the input on pin 3 goes to output pin 7 and input on pin 13 goes to output pin 9.
In the circuit shown D1 is input on pin 3 and D2 is input on pin 13 of 1st IC, while D3 is input on pin 3 and D4 is input on pin 13 of 2nd IC.
Thus when 1010 is given on these 4 parallel input pins
D1=1; D2=0; D3=1; D4=0
These inputs are provided to the 4 D- flip flops. Hence, when the clock pulse is applied the output becomes as follows:
Q1=1;Q2=0;Q3=1;Q4=0
(3)
When S0=S1=0 in 74LS153 IC the input on pin 6 goes to output pin 7 and input on pin 10 goes to output pin 9.
From previous operation Q1=1 is input on pin 6 and Q2=0 is input on pin 10 of 1st IC, while Q3=1 is input on pin 6 and Q4=0 is input on pin 10 of 2nd IC.
These inputs are again provided to the 4 D- flip flops. Hence, when the clock pulse is applied the output becomes as follows:
Q1=1;Q2=0;Q3=1;Q4=0
i.e output remains unchanged.
(4)
When S0= 0; S1=1 in 74LS153 IC the input on pin 4 goes to output pin 7 and input on pin 12 goes to output pin 9.
LSI=0 i.e. 0 is input on pin 4 of 1st IC.
From previous operation Q1=1 is input on pin 12 of 1st IC. Q2=0 is input on pin 4 and Q3=1 is input on pin 12 of 2nd IC.
With aplication of 1st clock pulse these inputs move to the output of flip flops. The outputs are as follows:
Q1=0;Q2=1;Q3=0;Q4=1
Now again
LSI=0 i.e. 0 is input on pin 4 of 1st IC.
From previous operation Q1=0 is input on pin 12 of 1st IC. Q2=1 is input on pin 4 and Q3=0 is input on pin 12 of 2nd IC.
With aplication of 2nd clock pulse these inputs move to the output of flip flops. The outputs are as follows:
Q1=0;Q2=0;Q3=1;Q4=0
(5)
When S0= 1; S1=0 in 74LS153 IC the input on pin 5 goes to output pin 7 and input on pin 11 goes to output pin 9.
RSI=1 i.e. 1 is input on pin 11 of 2nd IC.
From previous operation Q2=0 is input on pin 5 and Q3=1 is input on pin 11 of 1st IC. Q4=0 is input on pin 5 of 2nd IC.
With aplication of 1st clock pulse these inputs move to the output of flip flops. The outputs are as follows:
Q1=0;Q2=1;Q3=0;Q4=1
Now again
RSI=1 i.e. 1 is input on pin 11 of 2nd IC.
From previous operation Q2=1 is input on pin 5 and Q3=0 is input on pin 11 of 1st IC. Q4=1 is input on pin 5 of 2nd IC.
With aplication of 1st clock pulse these inputs move to the output of flip flops. The outputs are as follows:
Q1=1;Q2=0;Q3=1;Q4=1