Complete the following table of Trial 1(see Report sherry for determining the mo
ID: 483166 • Letter: C
Question
Complete the following table of Trial 1(see Report sherry for determining the molar volume of co, and the per- cent composition of CaCO, in a heterogeneous mixture. See Figure 134 and Equation 13.1. Record calculated values with the correct number of significant figures. A. Sample Preparation and Setup Apparatus Calcularian Zane I. Mass of sample (g) 0226 Part C7 2. Mass of generator sample before reaction (g) C. Determination of volume, Temperature, and Pressure of the Carbon Dioxide Gas 3. Volume of Co:Kg) collected (L) 4. Temperature of water Part D.2 5. Barometric pressure (torr) 6. vapor pressure of H O at 20.0°C 7. Pressure of dry Co.(gxiom D. Amount of Carbon Dioxide Gas Evolved 1. Mass of generator sample after reaction (gO -R2642 Part D 2. Mass loss of generator mass of CO: evolved (g) 3. Moles of Coxg) evolved (mo) Part E2 E. Molar Volume of Con Gas 2. Volume of CO.CR) at STP (L) 3. Molar volume of co20g) at STP (Uma) Part E3 F. Percent Caco, in Mixture Moles of Caco, in sample from mol 1. coh generated (mo) Part F.2 2. Mass of CaCO, in sample Cg) 3, Mass of original sample Gig) 4. Percent of Caco in sample 37.7 mL.Explanation / Answer
Q6.
Vapor pressure of water H2O (20°C) = 17.5424 torr
Q7.
P-CO2 = Ptotal - P vapor = 770-17.5424 = 752.4576 torr
D)
mass of CO2 = mol
PV = nRT
n = PV/(RT) = 752.4576/760*0.0377/(0.082*293) = 0.0015535 mol of CO2
mass = mol*MW = 0.0015535*44 = 0.068354 g of CO2
Q3.
moles = 0.0015535 mol
E
1 mol = 22.4 L
0.0015535 mol = 0.0015535*22.4 = 0.0347984 L approx
so..
AT STP --> 22.4 L / mol
F
Q1.
CaCO3 = CO2 = 0.0015535 moles
mas sof CaCO3 = mol*MW = 0.0015535 *100 = 0.15535 g of CaCO3
mass of samle = 0.276 g
% CaCO 3= 0.15535 /0.276 *100 = 56.2862 %