In the reactoin shown below, if 33.5 g of sodium reacts, and the hydrogen that\\
ID: 508693 • Letter: I
Question
In the reactoin shown below, if 33.5 g of sodium reacts, and the hydrogen that's produced is collected in a 3.5 L flask at 21.0 °C, what will be the pressure exerted by the gas (in atm)?
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2Na(s) + 2H2O(l) -------> 2NaOH(aq) + H2(g)
2 mol of sodium reacts give 1 mol of H2
Molar mass of Na = 22.99g
No of mol in 33.5 g = mass/molar mass
= 33.5g/22.9g
= 1.4572 mol
No of mol of H2 given by1.4572 mol of Na=1.4572/2= 0.7286
Ideal gas equation is
PV = nRT
P = nRT/V
P= pressure
R = gas constant , 0.082057 (Lit atm/mol K)
V = volume , 3.5 L
T= 21°C =294.15K
n = no of mol , 0.7286
Substituting the values
P = (0.7286 × 0.082057( L atm / mol K ) × 294.15 K)/3.5 L
= 5.02 atm
So, pressure exerted by the gas is 5.02 atm