Part 1. We will assume a classical cation anion balance calculation with only ma
ID: 524542 • Letter: P
Question
Part 1. We will assume a classical cation anion balance calculation with only major ions (Na K, Mg ca t, CI, so42, Hco3 Accordingly, moles positive charge moles 2+ negative charge (i e., electroneutrality, which must be true for any ionic solution). The classical assumption is that the above-mentioned ions are the major (explanatory) components and there are no other anions or cations that contribute significantly to the balance. If so, and the Evian data are precise and unbiased, one expects total cations (moles charge liter total anions within 2% After converting concentrations from mg/L to molarity, the balance can calculated as: Total cations MolesNaL001 mole charge 1 mole Na) (Moles KUL)(1 mole charge 1 mole K) (Moles Mg/L002 mole charge/ 1 mole Mg) (Moles CaL)(2 mole charge 1 mole Ca) Total anions Moles, CVL001 mole charge/ 1 mole C) (Moles HCO3/L)(1 mole charge/ 1 mole HCO3) (Moles SO4/L)(2 mole charge/ 1 mole so4) Balance B Total cations/Total anions (express as a ratio or percent to indicate relative balance) Check the cation-anion balance of the average water composition using average concentrations for the balance reported in Evian's 25 February 2014 Annual Water Quality Report For your 1 L bottle, use the label's ion content to calculate the missing Na concentration; compare this vs. anything stated in the 2014 Evian report.Explanation / Answer
Ans;- We will check the cation anion balance for the given analysis
Total cations = 4.04+0.291+0.025+1.125
= 5.481
Total anions = 0.253+0.27+5.73
= 6.253
Balance B= Total cations/Total anions
= 5.481/6.253
= 0.876
Solutes Measured concentration(mg/L) Atomic weight (g) Molarity =Given mass/molarmass valence charge milliequivalent=molarity x valence charge Ca2+ 81 40 81/40 = 2.02 2 2x2.02=4.04 Na+ 6.7 23 6.7/23=0.291 1 1x0.0291=0.291 K+ 1 39 1/39=0.025 1 1x0.025=0.025 Mg+ 27 24 27/24=1.125 1 1x1.125=1.125 Cl- 9 35.5 9/35.5=0.253 1 1x0.253=0.253 SO42- 13 96 13/96=0.135 2 2x0.135=0.27 HCO3- 350 61 350/61=5.73 1 1x5.73=5.73