Part 1. In the figure below, a cube with side length 3.81 cm encloses charges. O

Question

Part 1. In the figure below, a cube with side length 3.81 cm encloses charges.  One postive charge, +36.6 nC, and six negative charges, each with -4.1 nC.  The charges are arranged in the configuration shown such that the positive charge is in the center of the cube and the six negative charges are placed symmetrically about the central positive charge.  What is the total electric flux through the cube?

part. 2

If the charges were moved to be closer to the top face, but all seven charges remain within the cube, how would you answer to Question 1 change? would flux be larger, smaller, or same.

Part 3.

If the length of each edge of the cube was doubled, with the charges remaining in the center of the cube, what is the ratio of this new flux to your original flux in Question 1

In the figure below, a cube with side length 3.81 cm encloses charges. One postive charge, +36.6 nC, and six negative charges, each with -4.1 nC. The charges are arranged in the configuration shown such that the positive charge is in the center of the cube and the six negative charges are placed symmetrically about the central positive charge. What is the total electric flux through the cube?

Explanation / Answer

Qin = (36.6 - 6*4.1)*10^-9 = 12*10^-9 C

1) total flux = Qin/epsilon = 12*10^-9/8.854*10^-12 = 1.355*10^3 N/m^2/c

2) same

3) flux remins same. so the ratio becomes 1

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