For the Reactions that Occurred: You should know that group 1 metal cations and
ID: 542965 • Letter: F
Question
For the Reactions that Occurred: You should know that group 1 metal cations and nitrates will not precipitate, regardless of counterion. Therefore, you can now predict a reaction product for each mixture. 1) In the space below, if you have a solid that forms, you need to write the a) total ionic reaction and b) the net ionic reaction Make sure each reaction is properly balanced (atoms and charge), Make sure each solid has balanced cation and anion charge. Label the solids with (s). Example: Rxn: (AgNO3+NaCI): Total. Ag'(aq) + NOs(q) + Na"(aq) +cr(aq)AgCl(s) + Na'(aq)+NOS(aq) Ag+(aq) + Cl(aq) AgCl(s) Net: ito NRExplanation / Answer
1) 2NaOH(aq)+Ca(NO3)2(aq)--------> 2NaNO3(aq) + Ca(OH)2
Total ionic reaction
2Na+(aq) + 2OH-(aq) + Ca+2 aq) + 2NO3-(aq)--------> 2Na+-(aq) + OH-(aq) + Ca+2 aq) + 2NO3-(aq)-
Net ionic reaction:
No net ionic reaction as all are dissociated completely
2) 2Na+(aq) + 2OH-(aq) + Pb+2 aq) + 2NO3-(aq)--------> Pb(OH)2 (s) + 2Na+(aq) + 2NO3-(aq)
Net ionic reaction is
Pb+2 aq) +2OH-(aq) ------> Pb(OH)2 (s)
3) ionic reaction
4Na+ (aq) +(PO4-3) (aq) + OH- (aq) ---> 4Na+ (aq) +(PO4-3)(aq) + OH- (aq)
No net ionic reaction
4) CuSO4 + Na3PO4
The ionic equation will be
3Cu+2 (aq) + 3SO4-2 (aq) + 6Na+ (aq) + 2PO4-3 (aq) ---> Cu3(PO4)2 (s) + 6Na+ (aq) + 3SO4-2 (aq)
Net ionic equation will be
3Cu+2 (aq) + 2PO4-3 (aq) ---> Cu3(PO4)2 (s)
5) ionic
3 Na+ + PO43- + Fe3+ + 3 Cl- ---> FePO4 + 3Na+ + 3Cl-
net ionic
PO43- (aq) + Fe3+ (aq) ---> FePO4 (s)
6) Full ionic equation
3Ca2+(aq) + 6NO3-(aq) + 6Na+(aq) + 2PO43-(aq) Ca3(PO4)2(s) + 6Na+(aq) + 6NO3-(aq)
Net ionic equation
3Ca2+(aq) + 2PO43-(aq) Ca3(PO4)2(s)
7) full ionic equation
3 Pb2+ + 6 NO3- + 6 Na+ + 2 PO43- ---> Pb3(PO4)2 (s)+ 6 Na+ + 6 NO3-
Net ionic equation
3 Pb2+ + 2 PO43- ---> Pb3(PO4)2 (s)
8) Full ionic equation
Pb2+(aq) + 2NO3 - (aq) + Cu2+(aq) + SO42-(aq) PbSO4(s) + Cu2+(aq) + 2NO3-(aq)
Net ionic equation :
Pb2+(aq) + SO42-(aq) PbSO4(s)
9) FeCl3 + Pb(NO3)2
3Pb2+(aq) + 6NO3 - (aq) + 2Fe3+(aq) + 6Cl-(aq) PbCl2(s) + 2Fe3+(aq) + 6NO3 - (aq)
Net ionic equation :
3Pb2+(aq) + 3+ 6Cl-(aq) 3PbCl2(s)
10) Pb2+(aq) + 2NO3 - (aq) + Ca2+(aq) + 2NO3 - (aq) ---> Pb2+(aq) + 2NO3 - (aq) + Ca2+(aq) + 2NO3 - (aq)
No net equation
11) CuSO4 + Ca(NO3)2
Cu+2 (aq) + SO4-2 (aq) + Ca+2 (aq) + 2NO3- (aq) ---> CaSO4(s) + Cu+2 (aq) + 2NO3- (aq)
Net ionic
Ca+2 (aq) + SO4-2 (aq) ---> CaSO4(s)
12) FeCl3 + Ca(NO3)2
Overall
2Fe3+(aq) + 6Cl-(aq) + 3Ca2+(aq) + 6NO3 - (aq) ---> 2Fe3+(aq) + 6Cl-(aq) + 3Ca2+(aq) + 6NO3 - (aq)
No net ionic equation
13) CuSO4 + FeCl3
2Fe3+(aq) + 6Cl-(aq) + 3Cu2+(aq) + 3SO4 - (aq) ---> 2Fe2(SO4)3 (s) + 6Cl-(aq) + 3Cu2+(aq)
The net ionic equaiton will be
2Fe3+(aq) + 3SO4 - (aq) ---> 2Fe2(SO4)3