Part A Hydrogen peroxide (H202) decomposes in the presence of a catalyst to form

Question

Part A Hydrogen peroxide (H202) decomposes in the presence of a catalyst to form water and oxygen. The catalyst was added to 5 50 ml of a hydrogen peroxide solution at 250C, and 52.0 ml of gas was collected over water at a total pressure of 763.8 mmHg conditions in the table. Write and balance the chemical reaction (note: catalysts do not ap chemical equations) Express your answer as a chemical equation. Identify all of the answer. Look up the vapor pressure of water under these TABLE Vapor Pressure of Water versus Temperature Temperature ( c) Pressure Temperature (C) Pressure 2H202(aq) 2H20)+02(8) Submi Mv Answers Give Up (mmHg) (mmHg) 118.2 149.6 187.5 233.7 289.1 Correct 10 9.21 12.79 17.55 23.78 80 3186 42.23 55.40 71.97 70 Part B What is the partial pressure of oxygen collected over the water? Express your answer to one decimal place and include the app 433.6 525.8 45 100 760.0 0.03atm Submit Incorrect; Try Again; 9 attempts remaining Part C

Explanation / Answer

total pressure over mixture is due to vapours of water and oxygen gas.

vapour pressure of water vapour depands only on temperature.

so vapour pressure of water at 25' C = 23.78 mm of Hg

total pressure over mixutre = 763.8 mm of Hg

so pressure of oxygen gas = total pressure - vapour pressure of water

= 763.8 - 23.78

= 740.02 mm of Hg

so pressure of oxygen gas = 740.02 / 760 = 0.9737 atm

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---