CHE 210 Nov 10 2017 Take home Quiz 8 Please show all work to receive full credit
ID: 557334 • Letter: C
Question
CHE 210 Nov 10 2017 Take home Quiz 8 Please show all work to receive full credit Name: For the following reactions: 1) Name the reactants and products, 2) balance the equation, and 3) calculate the molecular mass of the reactants and products. Starting with 2.0 grams of each reactant, 4) identify the limiting reagent and 5) determine the mass of the first product. 1. For example CO(g) -2-FeO (s) CO2(g) + Fed, (s) + Name: iron (lll) oxide, carbon monoxide on (II) oxide carbon dioxide Molar mass: 159.69 g/mol 28.01 g/mol 71.844 g/mol 44.01 g/mol Mass: g Mole. 15949 g/mol =0.0 125 mol 2801 g/mol 0.07 14 mol Limiting reagent: 00125 melF0 7mhe FegO, is the limiting reagent Mass of first product: 0.0125 mol FeO,xm x784 1.7961 g Feo 2 g 2g FeO (s) CO (g) Fe (s) + CO2 (g) a. + b. _C,,Hy(Di (s) 02 (g) --H20 (g) + CO2 (g) +Explanation / Answer
FeO (s) + CO (g) = Fe (s) + CO2(g)
iron oxide carbon monoxide iron carbon dioxide
molar mass: 71.844 gm/mol 28.01 gm/mol 55.84gm/mol 44.01 gm/mol
mass 2gm 2gm
mole 0.0278 mole 0.0714 mole
limiting reagent: FeO
mass of first product: 0.0278 mole* 55.84 gm/mole =1.5523 gm
2. a.4 Al (s) +3O2 (g) = 2Al2O3
b. Na2O + CO2 = Na2CO3
c. Ca +2H2O = Ca(OH)2 + H2
d. 2KNO3 = 2KNO2 + O2
e. 3Ba + Fe2(SO4)3 = 3BaSO4 + 2Fe