Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Assume that you conduct a testcross (AaBb x aabb) and find that the recombinatio

ID: 55763 • Letter: A

Question

Assume that you conduct a testcross (AaBb x aabb) and find that the recombination frequency between a and b is 35% which would correspond to a map distance of 35 mu. Why is this value likely an underestimation of the true map distance between the two genes? How might you determine a more accurate map distance? (You don’t have to find a particular distance that would be more accurate, just describe how you would go about doing it?) Assume that you conduct a testcross (AaBb x aabb) and find that the recombination frequency between a and b is 35% which would correspond to a map distance of 35 mu. Why is this value likely an underestimation of the true map distance between the two genes? How might you determine a more accurate map distance? (You don’t have to find a particular distance that would be more accurate, just describe how you would go about doing it?) Assume that you conduct a testcross (AaBb x aabb) and find that the recombination frequency between a and b is 35% which would correspond to a map distance of 35 mu. Why is this value likely an underestimation of the true map distance between the two genes? How might you determine a more accurate map distance? (You don’t have to find a particular distance that would be more accurate, just describe how you would go about doing it?)

Explanation / Answer

AaBb x aabb

The recombination frequency between a and b is assumed as 35% and the map distance as 35mu. Actually the in the progeny produced, the recombinants should be10% and the 90% of the progeny should be like that of parents. Therefore, the map distance should be half of parental percentage that is 90/2 = 45. Hence, the map distance between a and b is about 45mu. It can be determined by detecting the recombination frquency.

Male/ Female A B a Aa aB b Ab Bb