May I please have a step by step answer on how to solve this. I\'m really trying
ID: 567272 • Letter: M
Question
May I please have a step by step answer on how to solve this. I'm really trying to understand what's going on here.
Thanks!
One of the tasks for your group is to prepare a solution of NaOH to be used later in the lab. Each group will be responsible for preparing 250 mL of a 0.1 M solution. The stock solution is 50.5% N OH weight by water. That means for every 100 g of solution, 50.5 g of it is Na he density o this 50.5%, Na solutions·4 How many mL of the stock solution do I need to dilute to 250 mL with DI water to get a 0.1 M solution? mLExplanation / Answer
molarity of stock solution first we need to find
molar mass of NaOH = 40 g / mol
mass % is given = 50.5 %
density = 1.54 g/mL
molarity = mass % x 10 x density / molar mass ----------------> formula
= 50.5 x 10 x 1.54 / 40
= 19.44 M
C1 = 19.44 M
V1 = ?
C2 = 0.1 M
V2 = 250 mL
dilution formula :
C1 V1 = C2 V2
19.44 x V1 = 0.1 x 250
V1 = 1.29 mL
volume of stock solution needed = 1.29 mL