Need help with this ratio question, Please show work. Suppose you make a mixture

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Need help with this ratio question, Please show work.

Suppose you make a mixture of Dye1 and Dye2 in a 2:1 volume ratio, respectively. Determine the expected absorbance values at 440 nm and 575 nm for this new solution.

Question #4 Consider two solutions of dyes, each at a given concentration. These solutions are named Dye1 and Dye2. The Amax for Dye1 is 440 nm, and Amax for Dye2 is 575 nm. You run visible spectra for each solution and get the following absorbance values at the two wavelengths: 440 575 Dye1 0.712 0.004 Dye2 0.019 0.519 Part 1: Suppose you mix 5.00 mL of each solution together. Determine the expected absorbance values at 440 nm and 575 nm for this new solution | 575 0.3660.262 Ok 440 Ok Your results are now shown above

Explanation / Answer

We are mixing it in a ratio of 2:1. it means we take two parts of Dye1 and 1 part of dye 1.
From the given ratio calculate the average absorbance:
For 440 nm:
Expected absorbance = (2xDye1 Abs + 1xDye2 Abs)/ 3
= (2x0.712 + 1x0.019)/3
   =0.481
For 575 nm:
Expected absorbance = (2xDye1 Abs + 1xDye2 Abs)/ 3
= (2x0.004 + 1x0.519)/3
   = 0.176

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