Please help me to solve this fully Chem 18 Post-Laboratory Quia Name Lab Day and

Question

Please help me to solve this fully

Chem 18 Post-Laboratory Quia Name Lab Day and Hour Analysis of Al-n Alloy A 0.1465 g A-n alie umple was reactod in wold so produce 184.5 ml hydrogen gs over waterat 212"C and 752.2rsctri pressare Vaporpressure o t 21 2-C is 18,880 tor and R-0.08206 L atmK mol Calcalae the Partial Pressare of Hydrogen gas peoduced 2Celoulate the moles of Hydrogon ga prodasod Caloulate Niu: (the moles of hydroge per gr a The 6 M HCI is a isirty soncantrated solution of ICL Name one precadion that hodbe when handling this selution, and why this is important

Explanation / Answer

Q1

P-Gas

from

Ptotal = Pwater vapor + P-hydrogen

752.2 mm Hg = 18.88 mm Hg + P-H

P-hydrogen = 752.2-18.88 = 733.32 mm Hg

Q2.find moles of H2

PV = nRT

n = PV/(RT)

n = (733.32)(184.5/1000)/(62.4*(21.2+273.15)

n = 0.007366 mol of H2gas

Q3.

mass of alloy --> 0.1465 g

Ratio = mol/mass = 0.007366/0.1465 = 0.050279

Q4

precaution --> do not inhale fumes of HCl, do NOT touch solution, this irrates skin/eyes/respairatory tract

Avoid addition of acid massively, add dropwise, since it is very reactivE/violent

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