In Figure ( a ), both batteries have emf ? = 1.40 V and the external resistance
ID: 581231 • Letter: I
Question
In Figure (a), both batteries have emf ? = 1.40 V and the external resistance R is a variable resistor. Figure (b) gives the electric potentials V between the terminals of each battery as functions of R: Curve 1 corresponds to battery 1, and curve 2 corresponds to battery 2. The horizontal scale is set by Rs = 0.300 ?. What is the internal resistance of (a) battery 1 and (b) battery 2?
In Figure (a), both batteries have emf E 3 1.40 V and the external resistance Ris a variable resistor. Figure (b) gives the electric potentials V between the terminals of each battery as functions of R Curve 1 corresponds to battery 1, and curve 2 corresponds to battery 2. The horizontal scale is set by Rs 0.300 2. What is the internal resistance of (a) battery 1 and (b) battery 2? 0.70 0.420. R (2) (a) (b)Explanation / Answer
Total voltage V =1.4+1.4=2.8volt
Total current I=V/Rs=2.8/0.3=9.33A
A) internal resistance of battery 1=0.7/9.33= 0.075 ohm
B) internal resistance of battery 2= 0.42/9.33= 0.045 ohm