A sample of a gas has a volume of 1380 mL at a temperature of 20.0C what will be
ID: 589102 • Letter: A
Question
A sample of a gas has a volume of 1380 mL at a temperature of 20.0C what will be it’s volume at 0.0C if the pressure remains constant ?I’m having a little bit of trouble here setting this up . I have to show all my work
This is what I came up with so far but decided to ask to help
Vi 1380 ML Ti 20.0 V2 ? T2 293k
1380 x 293k Over 760 x 273
Is this even the correct formula ?
Can you please help me understand this problem and show work.
Pv=nRt maybe ?
I appreciate your help very much thanks :) A sample of a gas has a volume of 1380 mL at a temperature of 20.0C what will be it’s volume at 0.0C if the pressure remains constant ?
I’m having a little bit of trouble here setting this up . I have to show all my work
This is what I came up with so far but decided to ask to help
Vi 1380 ML Ti 20.0 V2 ? T2 293k
1380 x 293k Over 760 x 273
Is this even the correct formula ?
Can you please help me understand this problem and show work.
Pv=nRt maybe ?
I appreciate your help very much thanks :)
I’m having a little bit of trouble here setting this up . I have to show all my work
This is what I came up with so far but decided to ask to help
Vi 1380 ML Ti 20.0 V2 ? T2 293k
1380 x 293k Over 760 x 273
Is this even the correct formula ?
Can you please help me understand this problem and show work.
Pv=nRt maybe ?
I appreciate your help very much thanks :)
Explanation / Answer
Ans. Charles’ Law: Volume (V) of a gas in a closed vessel is directly proportional to absolute temperature (T, in kelvin).
That is, V1 / T1 = V2 / T2 - Pressure constant - equation 1
Note: the temperature must be in terms of “absolute temperature, kelvin”.
Given, T1 = 20.00C = 293.15 K ; T2 = 0.00C = 273.15 K
Putting the values in equation 1-
1380 mL / 293.15 K = V2 / 273.15 K
Or, V2 = (1380 mL / 293.15 K) x 273.15 K
Hence, V2 = 1285.85 mL
Therefore, Volume of gas at 0.00C = 1285.85 mL
Note: There is no need of calculating the moles of gas at 20.00C using ideal gas equation (PV = nRT) and then fitting the value of “n” at 0.00C to get new value. Charles’s law jus does the same thing.