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Can someone explain in detail how to do this problem? How many liters of Cl 2 ga

ID: 680224 • Letter: C

Question

Can someone explain in detail how to do this problem? How many liters of Cl2 gas at STP are produced bythe reaction of 30.0 mL of a 12.0 M solution of HCl? (That is,there are 12.0 mol HCl per liter of solution.) There is an excessof KMnO4. The reaction is 2KMnO4 + 16 HCl = 2 KCl + 2 MnCl2+5Cl2 + 8 H2O Answer: 2.52 L Cl2 Can someone explain in detail how to do this problem? How many liters of Cl2 gas at STP are produced bythe reaction of 30.0 mL of a 12.0 M solution of HCl? (That is,there are 12.0 mol HCl per liter of solution.) There is an excessof KMnO4. The reaction is 2KMnO4 + 16 HCl = 2 KCl + 2 MnCl2+5Cl2 + 8 H2O Answer: 2.52 L Cl2 Can someone explain in detail how to do this problem? How many liters of Cl2 gas at STP are produced bythe reaction of 30.0 mL of a 12.0 M solution of HCl? (That is,there are 12.0 mol HCl per liter of solution.) There is an excessof KMnO4. The reaction is 2KMnO4 + 16 HCl = 2 KCl + 2 MnCl2+5Cl2 + 8 H2O Answer: 2.52 L Cl2

Explanation / Answer

Number of moles of HCl = (Molarity * V ml ) / 1000                                       = 0.36 moles 2KMnO4 + 16 HCl = 2 KCl + 2 MnCl2+5Cl2 + 8 H2O                    16 moles of HCl    gives        5*22.4 L ofCL2    atSTP         
                    0.36 moles of HCl    gives    x moles of Cl2
                                       x =(5*22.4*0.36 )/ 16                                              =2.52 L