If you were going to graphically determine the enthalpy AH\", for this reaction,

Question

If you were going to graphically determine the enthalpy AH", for this reaction, what points would you plot? order reaction was measured at two temperatures, T. The data is shown in this table Number Number To avoid rounding T(K) K 325 3.76 875 6.44 errors, use three significant figures in the x values and four significant figures in the y values point 1: Number Number point 2: Determine the rise, run, and slope of the line formed by these points. rise run slope Number Number Number What is the standard enthalpy of this reaction? Number J/ mol

Explanation / Answer

The graph will be plotted between ln(K) and 1/T

Point 1: x = 1/325 = 0.00308 (rounded to three decimal places), y = ln(3.76) = 1.324

Point 2: x = 1/875= 0.00114 (rounded to three decimal places), y = ln(6.44) = 1.863

rise = y2-y1 = 1.863 - 1.324 = 0.539

run = x2 - x1 = 0.00114  - 0.00308 = -0.00194

Slope = rise/run = 0.539/(-0.00194) = -277.8

Delta H = -Slope * R = -277.8 * 8.314 = 2309.6 J/mol

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---