If you were going to graphically determine the activation energy of this reactio
ID: 1042811 • Letter: I
Question
If you were going to graphically determine the activation energy of this reaction, what points would you plot? nsider this reaction data A > products Number Number T (K) k (s) 325 825 To avoid rounding errors, use at least three significant fiqures in all values point 1 0.391 0.824 Number Number point 2: Determine the rise, run, and slope of the line formed by these points rise run slope Number Number Number What is the activation energy of this reaction? Number J/ mol Previous Give Up&View; Solution Check Answer NextExitExplanation / Answer
We need to plot lnK on y axis and 1/T on x axis
K = 0.391
ln K = ln (0.391) = -0.93905
T = 325.0
1/T = 0.00308
point 1 is:
x = 0.00308
y = -0.93905
K = 0.824
ln K = ln (0.824) = -0.19358
T = 825.0
1/T = 0.00121
point 2 is:
x = 0.00121
y = -0.19358
----------------------------------------------------------------------------
rise = (y1-y2) = -0.93905 - -0.19358 = -0.74546
rise = (X1-X2) = 0.00308 - 0.00121 = 0.00186
slope = rise/run
= -0.74546/0.00186
= -399.75452
----------------------------------------------------------------------------
use
slope = - Ea/R
= -399.75452 = -Ea/8.314
Ea = 3324 J/mol