If you were going to graphically determine the activation energy of this reactio
ID: 971068 • Letter: I
Question
If you were going to graphically determine the activation energy of this reaction, what points would you plot? Consider this reaction data: You can check your answers. You can view solutions when you up on any question. You can keep trying to answer ea you get it right or give up. You lose 5% of the points availab in your question for each incorre answer. To avoid rounding errors, use at least three significant figures in all values. Determine the rise, run, and slope of the line formed by these points. What is the activation energy of this reaction?Explanation / Answer
From Arhenius law
K= Ko*e-Ea/RT
Where K= rate constant and Ko=Frequency factor
Ea= Activation energy and T= temperature
Taking ln, the equation becomes
lnK= lnK0- Ea/RT
So a plot of lnK vs 1/T gives slope –Ea/R
( x axis ) ( 1/T ) y axis lnK
1/275=0.003636 ln(0.381)=-0.96496
1/825=0.001212 ln(0.605)=-0.50253
Run = 0.003636-0.001212=0.002424 and rise = -0.50253+0.96496=0.46243
Slope= -rise/ run = -0.46243/0.002424=-190.7715
Slope =-Ea/R= 190.7715, Ea= 190.7715*8.314 J/mole.K=1586 J/mole