Mastering Chemistry-ECT ehtmicourseld 14761969&OpenVellumHMAC; 41b1 41bcQ Search

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Mastering Chemistry-ECT ehtmicourseld 14761969&OpenVellumHMAC; 41b1 41bcQ Search CHE 140 -Tmbe lake se signments Homework 24: Percent Yield Limiting Reactant and Yield: Mole Calculations 2 af 9 onant Bensdic Table Part A when exposed to ar, alumnum metal Al, reacts with axygen, O2, to produce a protecthe coating of aluminum axode, AlOs. which prevents the aluminum trom usting undemeath. The balanced reaction is shown here What is the theoresical yield of aluminum cxide 3.20 mal of auminum metal is exposed to 2 70 mol of oxygen? Expeess your answer with the appropriate units P View Available Hins alte mol X Incorrect: Try Again;s attempts remaining Part B Complete previous partis) hoa

Explanation / Answer

The reaction is 4Al + 3O2 -------->2Al2O3

4 moles of Al reacts with 3 moles of O2 to give 2 moles of Al2O3.

Theoretical moles ratio of Al:O2= 4:3, dividing by the smallest number 3, the moles ratio becomes

Al:O2= 4/3:3= 1.33: 1.

given moles of Al= 3.2 and moles of O2= 2.7

So actual moles ratio of Al:O2= 3.2 :2.7, dividing by 2.7, the ratio becomes

Al :O2= 3.2/2.7 :1 =1.19:1

This ratio suggests, the limiting reactant is Al and the Al reacts,

hence 4 mole of Al from the stouchometry suggest to give 2moles of Al2O3

3.2 moles of Al consumes 3.2*3/4=2.4 moles of O2 to give 2*3.2/4= 1.6 moles of Al2O3.

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