Colligative Constants Constants for freezing-point depression and boiling-point

Question

Colligative Constants Constants for freezing-point depression and boiling-point elevation calculations at 1 atr SolventFormula Kf value*Normal freezing Kb value Normal boiling point (c 0.00 5.49 point (oc) oC/m 1.86 5.12 0.512100.00 2.53 2.92 1.22 5.03 H20 water benzene cyclohexane C6H12 20.8 6.59 ethanol carbon tetrachloride camphor 80.1 80.7 78.4 76.8 C6H6 C2H601.99 -117.3 CCI4 | 29.8 |-22.9 C10H160 37.8 176 "When using positive Kf values, assume that is the absolute value of the change in t temperature, then will be negative and so you must use negative Kf values. Either w solvent. Comments

Explanation / Answer

Tf = i*Kf*m

Tf = 3.70

Kf for water = 1.86/m

m = 0.810m

i = Tf/Kf*m = 3.70/1.86/m*0.810m

i = 2.45

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