Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Map Sapling Learning A solution of HNO3 is standardized by reaction with pure so

ID: 714772 • Letter: M

Question

Map Sapling Learning A solution of HNO3 is standardized by reaction with pure sodium carbonate A volume of 25.95 ± 0.06 mL of HNO3 solution was required for complete reaction with 0.8417 ± 0.0008 g of Na2CO3. (FM 105.988 + 0.001). Find the molarity of the HNO3 and its absolute uncertainty. Note: Significant figures are graded for this problem. To avoid rounding errors, do not MI M round your answers until the very end of your calculations Previous Give Up & View Solution Check Answer NextExit

Explanation / Answer

Ans. Moles of Na2CO3 consumed = Mass / MW

                                                            = (0.8417 ± 0.0008) g / (105.988 ± 0.001) g mol-1

                                                            = (0.007941 ± 0.000008) mol

# Following stoichiometry of balanced reaction, 1 mol HNO3 (= H+) is neutralized by 1 mol Na2CO3.

So,

            Moles of HNO3 in sample = 2 x Moles of Na2CO3

                                                            = 2 x (0.007941 ± 0.000008) mol

                                                            = (0.01588 ± 0.00002) mol

# Given, volume of HNO3 solution = (25.95 ± 0.06 mL) = (0.02595 ± 0.00006) L

Now,

            [HNO3] = Moles of HNO3 / Vol. of soln. in liters

                        = (0.01588 ± 0.00002) mol / (0.02595 ± 0.00006) L

                        = (0.6121 ± 0.002) M